Law of Logarithm
Loga1 =
0
Logam +
logan = loga(m x n)
Logab n
= n x logab
Logam –
logan = loga(m/n)
Example:-
1. Write the following indices to logarithms form:-
a) 52 = 25
b) 1642
c) 125 = 53
Answer:-
a) Log525 = 2
b) Log416 =2
c) Log5125 = 3
2. Write is log5625?
Log5625
= ?
5x = 625
5x = 54
Log5625
= 4
3. Log77 + 4log73-2log79
= 1 + log734
– log792
= 1 + log781
– log781
= 1
4. Solve the equation:-
Log3 (2 +
x) = 4
Log34
= 2 + x
81 = 2 + x
81 – 2 + x
79 = x
it is easy to understand.
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