Wednesday 4 May 2016

Logarithm

Law of Logarithm
Loga1 = 0
Logam + logan = loga(m x n)
Logab n = n x logab

Logam – logan = loga(m/n)


Example:-
1.   Write the following indices to logarithms form:-
a)   52 = 25
b)   1642
c)   125 = 53

Answer:-
a)   Log525 = 2
b)   Log416 =2
c)   Log5125 = 3

2.   Write is log5625?
Log5625 = ?
5x = 625
5x = 54
Log5625 = 4


3.   Log77 + 4log73-2log79

= 1 + log734 – log792
= 1 + log781 – log781
= 1

4.   Solve the equation:-
Log3 (2 + x) = 4
Log34 = 2 + x
81 = 2 + x
81 – 2 + x

79 = x

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